8월, 2019의 게시물 표시

Open interval in R is open set

Let (a,b)  = \{ x \in R \mid a < x < b\} Let c \in (a, b) and define \epsilon-neighborhood of c as N_\epsilon (c) = \{x \in R \mid \ |x - c| < \epsilon \} Take \epsilon < min\{ b - c, c - a\}. x \in N_\epsilon (c) \Longrightarrow |x - c| < \epsilon \Longleftrightarrow c - \epsilon < x < c + \epsilon Since \epsilon < b - c and \epsilon < c - a, a < x < b could be rewritten as a = c - (c - a) < c - \epsilon < x < c + \epsilon < b = c - (b - c) \Longleftrightarrow x \in (a, b) \Longrightarrow N_\epsilon (c) \subseteq  (a, b)